Salineville

Village in Columbiana County, Ohio

View of Salineville, Ohio
Photo: Derek Jensen (Tysto) · Public domain

Salineville is a village in Columbiana County, Ohio, with 1,206 residents (2020 Census). It sits at 899 ft (274 m) above sea level. The nearest town is Summitville, 4.6 miles NW.

About Salineville

Salineville ( sə-LEEN-vil

) is a village in Columbiana County, Ohio, United States. The population was 1,206 at the 2020 census.

Text: Wikipedia · CC BY-SA 4.0

Salineville weather: 7-day forecast

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Source: National Weather Service (NOAA).

Live webcams in Salineville

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Living in Salineville

Median household income
$47,917
Median home value
$89,700
Median rent
$810/mo
Median age
40.4
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Map of Salineville

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Salineville Street View

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Salineville, OH population

Salineville had 1,206 residents in the 2020 Census.

2020 Census1,206
Density546 per sq mi (211 per km²)

Source: U.S. Census Bureau, Decennial Census.

Salineville at a glance

StateOhio (OH)
CountyColumbiana County
TypeVillage
Population1,206 (2020)
Land area2.21 sq mi (5.7 km²)
Elevation899 ft (274 m)
Coordinates40.6207° N, 80.8344° W
ZIP code43945
Census code (GEOID)3970100

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Salineville

Straight-line distance between town centers.

Frequently asked questions about Salineville

What county is Salineville in?

Salineville is in Columbiana County, Ohio.

What is the population of Salineville, OH?

1,206 people lived in Salineville at the 2020 Census.

What is the ZIP code of Salineville, OH?

The ZIP code of Salineville is 43945.

What is the elevation of Salineville?

899 feet (274 m) above sea level.

What towns are near Salineville?

Summitville (4.6 mi), Irondale (6.6 mi), Bergholz (7.4 mi), Wellsville (9.4 mi), Hanoverton (10.7 mi).

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