Bergholz

Village in Jefferson County, Ohio

View of Bergholz, Ohio
Photo: Roseohioresident · CC BY-SA 4.0

Bergholz is a village in Jefferson County, Ohio, with 544 residents (2020 Census). It sits at 925 ft (282 m) above sea level. The nearest town is Amsterdam, 3.9 miles SW.

About Bergholz

Bergholz ( BURG-holes) is a village in Jefferson County, Ohio, United States. The population was 544 at the 2020 census. The village's name is German and translates to "mountain timber". It is part of the Weirton–Steubenville metropolitan area.

Text: Wikipedia · CC BY-SA 4.0

Bergholz weather: 7-day forecast

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Source: National Weather Service (NOAA).

Live webcams in Bergholz

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Living in Bergholz

Median household income
$56,875
Median home value
$65,300
Median rent
$783/mo
Median age
40.7
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Map of Bergholz

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Bergholz Street View

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Bergholz, OH population

Bergholz had 544 residents in the 2020 Census.

2020 Census544
Density966 per sq mi (373 per km²)

Source: U.S. Census Bureau, Decennial Census.

Bergholz at a glance

StateOhio (OH)
CountyJefferson County
TypeVillage
Population544 (2020)
Land area0.56 sq mi (1.5 km²)
Elevation925 ft (282 m)
Coordinates40.5208° N, 80.8851° W
ZIP code43908
Census code (GEOID)3905718

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Bergholz

Straight-line distance between town centers.

Frequently asked questions about Bergholz

What county is Bergholz in?

Bergholz is in Jefferson County, Ohio.

What is the population of Bergholz, OH?

544 people lived in Bergholz at the 2020 Census.

What is the ZIP code of Bergholz, OH?

The ZIP code of Bergholz is 43908.

What is the elevation of Bergholz?

925 feet (282 m) above sea level.

What towns are near Bergholz?

Amsterdam (3.9 mi), East Springfield (5.2 mi), Salineville (7.4 mi), Richmond (8.5 mi), Irondale (9.1 mi).

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