Waukau

Census-designated place in Winnebago County, Wisconsin

View of Waukau, Wisconsin
Photo: Royalbroil · CC BY-SA 3.0

Waukau is an unincorporated community (census-designated place) in Winnebago County, Wisconsin, with 302 residents (2020 Census). It sits at 833 ft (254 m) above sea level. The nearest town is Eureka, 3.9 miles NW.

About Waukau

Waukau is an unincorporated census-designated place in the town of Rushford, in Winnebago County, Wisconsin, United States. The community is located on Wisconsin Highway 116 at its southern terminus at Wisconsin Highway 91. As of the 2020 census, Waukau had a population of 302.

Text: Wikipedia · CC BY-SA 4.0

Waukau weather: 7-day forecast

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Living in Waukau

Median home value
$189,400
Median age
56.8
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Map of Waukau

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Waukau, WI population

Waukau had 302 residents in the 2020 Census.

2020 Census302
Density217 per sq mi (84 per km²)

Source: U.S. Census Bureau, Decennial Census.

Waukau at a glance

StateWisconsin (WI)
CountyWinnebago County
TypeCensus-designated place
Population302 (2020)
Land area1.39 sq mi (3.6 km²)
Water area0.01 sq mi (0.03 km²)
Elevation833 ft (254 m)
Coordinates43.9845° N, 88.7721° W
ZIP code54980
Census code (GEOID)5584200

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Waukau

Straight-line distance between town centers.

Frequently asked questions about Waukau

What county is Waukau in?

Waukau is in Winnebago County, Wisconsin.

What is the population of Waukau, WI?

302 people lived in Waukau at the 2020 Census.

What is the ZIP code of Waukau, WI?

The ZIP code of Waukau is 54980.

What is the elevation of Waukau?

833 feet (254 m) above sea level.

What towns are near Waukau?

Eureka (3.9 mi), Omro (4.1 mi), Berlin (8.9 mi), Winneconne (9.4 mi), Butte des Morts (9.9 mi).

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