Brandon
Town in Rutland County, Vermont
Brandon is a town in Rutland County, Vermont, with 4,129 residents (2020 Census). It sits at 427 ft (130 m) above sea level. The nearest town is Leicester, 4.9 miles N.
- 4,129residents (2020 Census)
- 427 ftelevation · 130 m
- 39.7 sq miland area · 102.9 km²
- 104 / sq mipopulation density
- 05733ZIP code
About Brandon
Brandon is a town in Rutland County, Vermont, United States. As of the 2020 census, the population was 4,129.
Text: Wikipedia · CC BY-SA 4.0
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Living in Brandon
- Median household income
- $64,180
- Median home value
- $227,800
- Median rent
- $1,064/mo
- Median age
- 50.1
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Map of Brandon
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Open in Google Maps ›Brandon, VT population
Brandon had 4,129 residents in the 2020 Census.
| 2020 Census | 4,129 |
|---|---|
| Density | 104 per sq mi (40 per km²) |
Source: U.S. Census Bureau, Decennial Census.
Brandon at a glance
| State | Vermont (VT) |
|---|---|
| County | Rutland County |
| Type | Town |
| Population | 4,129 (2020) |
| Land area | 39.73 sq mi (102.9 km²) |
| Water area | 0.22 sq mi (0.58 km²) |
| Elevation | 427 ft (130 m) |
| Coordinates | 43.8053° N, 73.0753° W |
| ZIP code | 05733 |
| Official website | townofbrandon.com |
| Census code (GEOID) | 5002107750 |
Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.
Towns near Brandon
- Leicester4.9 mi N
- Sudbury5.0 mi W
- Goshen5.9 mi NE
- Hubbardton6.6 mi SW
- Pittsford6.7 mi S
- Whiting8.4 mi NW
- Salisbury8.5 mi N
- Chittenden9.1 mi E
- Orwell10.1 mi W
- Hancock10.4 mi NE
- Proctor10.7 mi S
- Castleton11.4 mi S
Straight-line distance between town centers.
Frequently asked questions about Brandon
What county is Brandon in?
Brandon is in Rutland County, Vermont.
What is the population of Brandon, VT?
4,129 people lived in Brandon at the 2020 Census.
What is the ZIP code of Brandon, VT?
The ZIP code of Brandon is 05733.
What is the elevation of Brandon?
427 feet (130 m) above sea level.
What towns are near Brandon?
Leicester (4.9 mi), Sudbury (5.0 mi), Goshen (5.9 mi), Hubbardton (6.6 mi), Pittsford (6.7 mi).
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