Sabina

Village in Clinton County, Ohio

View of Sabina, Ohio
Photo: Aesopposea · CC BY-SA 3.0

Sabina is a village in Clinton County, Ohio, with 2,499 residents (2020 Census). It sits at 1,050 ft (320 m) above sea level. The nearest town is Milledgeville, 7.5 miles N.

About Sabina

Sabina ( sə-BY-nə) is a village in Clinton County, Ohio, United States. As of the 2020 census, the village had a total population of 2,499.

Text: Wikipedia · CC BY-SA 4.0

Sabina weather: 7-day forecast

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Living in Sabina

Median household income
$48,750
Median home value
$95,900
Median rent
$828/mo
Median age
44.2
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Map of Sabina

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Sabina, OH population

Sabina had 2,499 residents in the 2020 Census.

2020 Census2,499
Density2,125 per sq mi (820 per km²)

Source: U.S. Census Bureau, Decennial Census.

Sabina at a glance

StateOhio (OH)
CountyClinton County
TypeVillage
Population2,499 (2020)
Land area1.18 sq mi (3.0 km²)
Water area0.01 sq mi (0.02 km²)
Elevation1,050 ft (320 m)
Coordinates39.4909° N, 83.6353° W
ZIP code45169
Census code (GEOID)3969400

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Sabina

Straight-line distance between town centers.

Frequently asked questions about Sabina

What county is Sabina in?

Sabina is in Clinton County, Ohio.

What is the population of Sabina, OH?

2,499 people lived in Sabina at the 2020 Census.

What is the ZIP code of Sabina, OH?

The ZIP code of Sabina is 45169.

What is the elevation of Sabina?

1,050 feet (320 m) above sea level.

What towns are near Sabina?

Milledgeville (7.5 mi), Bowersville (7.8 mi), Octa (8.6 mi), Port William (9.1 mi), Highland (10.3 mi).

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