Sexton

Census-designated place in Kossuth County, Iowa

View of Sexton, Iowa
Photo: Brandonrush · Public domain

Sexton is an unincorporated community (census-designated place) in Kossuth County, Iowa, with 46 residents (2020 Census). It sits at 1,220 ft (372 m) above sea level. The nearest town is St. Benedict, 2.6 miles SE.

About Sexton

Sexton is an unincorporated community and census-designated place (CDP) in Irvington Township, Kossuth County, Iowa, United States. It is located at the intersection of U.S. Route 18 and Kossuth CR P60. As of the 2020 census it had a population of 46.

Text: Wikipedia · CC BY-SA 4.0

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Map of Sexton

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Sexton, IA population

Sexton had 46 residents in the 2020 Census.

2020 Census46
Density21 per sq mi (8 per km²)

Source: U.S. Census Bureau, Decennial Census.

Sexton at a glance

StateIowa (IA)
CountyKossuth County
TypeCensus-designated place
Population46 (2020)
Land area2.20 sq mi (5.7 km²)
Elevation1,220 ft (372 m)
Coordinates43.0749° N, 94.0892° W
ZIP code50483
Census code (GEOID)1971715

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Sexton

Straight-line distance between town centers.

Frequently asked questions about Sexton

What county is Sexton in?

Sexton is in Kossuth County, Iowa.

What is the population of Sexton, IA?

46 people lived in Sexton at the 2020 Census.

What is the ZIP code of Sexton, IA?

The ZIP code of Sexton is 50483.

What is the elevation of Sexton?

1,220 feet (372 m) above sea level.

What towns are near Sexton?

St. Benedict (2.6 mi), Wesley (5.0 mi), Irvington (6.9 mi), Algona (7.2 mi), Corwith (8.9 mi).

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