Jacksonville

Census-designated place in Shelby County, Iowa

Aerial view of Jacksonville, Iowa
Aerial view: USDA NAIP · USGS The National Map (public domain)

Jacksonville is an unincorporated community (census-designated place) in Shelby County, Iowa, with 29 residents (2020 Census). The nearest town is Kimballton, 4.2 miles E.

About Jacksonville

Jacksonville is an unincorporated community and census-designated place (CDP) in Jackson Township, Shelby County, Iowa, in the United States. As of the 2020 Census the population of Jacksonville was 29.

Text: Wikipedia · CC BY-SA 4.0

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Map of Jacksonville

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Jacksonville, IA population

Jacksonville had 29 residents in the 2020 Census.

2020 Census29
Density295 per sq mi (114 per km²)

Source: U.S. Census Bureau, Decennial Census.

Jacksonville at a glance

StateIowa (IA)
CountyShelby County
TypeCensus-designated place
Population29 (2020)
Land area0.10 sq mi (0.3 km²)
Coordinates41.6451° N, 95.1517° W
ZIP code51543
Census code (GEOID)1939180

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Jacksonville

Straight-line distance between town centers.

Frequently asked questions about Jacksonville

What county is Jacksonville in?

Jacksonville is in Shelby County, Iowa.

What is the population of Jacksonville, IA?

29 people lived in Jacksonville at the 2020 Census.

What is the ZIP code of Jacksonville, IA?

The ZIP code of Jacksonville is 51543.

What towns are near Jacksonville?

Kimballton (4.2 mi), Elk Horn (5.9 mi), Kirkman (8.3 mi), Harlan (9.0 mi), Corley (10.3 mi).

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