Hayesville

City in Keokuk County, Iowa

Aerial view of Hayesville, Iowa
Aerial view: USDA NAIP · USGS The National Map (public domain)

Hayesville is a city in Keokuk County, Iowa, with 41 residents (2020 Census). It sits at 797 ft (243 m) above sea level. The nearest town is Sigourney, 5.3 miles NE.

About Hayesville

Hayesville is a city in Keokuk County, Iowa, United States. The population was 41 at the time of the 2020 census.

Text: Wikipedia · CC BY-SA 4.0

Hayesville weather: 7-day forecast

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Live webcams in Hayesville

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Living in Hayesville

Median home value
$69,000
Median age
61.3
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Map of Hayesville

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Hayesville Street View

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Hayesville, IA population

Hayesville had 41 residents in the 2020 Census.

2020 Census41
Density164 per sq mi (63 per km²)

Source: U.S. Census Bureau, Decennial Census.

Hayesville at a glance

StateIowa (IA)
CountyKeokuk County
TypeCity
Population41 (2020)
Land area0.25 sq mi (0.6 km²)
Elevation797 ft (243 m)
Coordinates41.2648° N, 92.2478° W
ZIP code52562
Census code (GEOID)1935445

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Hayesville

Straight-line distance between town centers.

Frequently asked questions about Hayesville

What county is Hayesville in?

Hayesville is in Keokuk County, Iowa.

What is the population of Hayesville, IA?

41 people lived in Hayesville at the 2020 Census.

What is the ZIP code of Hayesville, IA?

The ZIP code of Hayesville is 52562.

What is the elevation of Hayesville?

797 feet (243 m) above sea level.

What towns are near Hayesville?

Sigourney (5.3 mi), Delta (5.9 mi), Martinsburg (5.9 mi), Hedrick (7.2 mi), Ollie (9.3 mi).

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