Harcourt

City in Webster County, Iowa

Aerial view of Harcourt, Iowa
Aerial view: USDA NAIP · USGS The National Map (public domain)

Harcourt is a city in Webster County, Iowa, with 264 residents (2020 Census). It sits at 1,175 ft (358 m) above sea level. The nearest town is Dayton, 5.3 miles E.

About Harcourt

Harcourt is a city in Webster County, Iowa, United States. The population was 264 at the time of the 2020 census.

Text: Wikipedia · CC BY-SA 4.0

Harcourt weather: 7-day forecast

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Living in Harcourt

Median household income
$72,708
Median home value
$85,000
Median rent
$550/mo
Median age
43.9
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Map of Harcourt

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Harcourt Street View

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Harcourt, IA population

Harcourt had 264 residents in the 2020 Census.

2020 Census264
Density261 per sq mi (101 per km²)

Source: U.S. Census Bureau, Decennial Census.

Harcourt at a glance

StateIowa (IA)
CountyWebster County
TypeCity
Population264 (2020)
Land area1.01 sq mi (2.6 km²)
Elevation1,175 ft (358 m)
Coordinates42.2606° N, 94.1745° W
ZIP code50544
Census code (GEOID)1934410

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Harcourt

Straight-line distance between town centers.

Frequently asked questions about Harcourt

What county is Harcourt in?

Harcourt is in Webster County, Iowa.

What is the population of Harcourt, IA?

264 people lived in Harcourt at the 2020 Census.

What is the ZIP code of Harcourt, IA?

The ZIP code of Harcourt is 50544.

What is the elevation of Harcourt?

1,175 feet (358 m) above sea level.

What towns are near Harcourt?

Dayton (5.3 mi), Gowrie (6.0 mi), Boxholm (7.0 mi), Paton (7.8 mi), Lehigh (9.2 mi).

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