Fredonia
City in Louisa County, Iowa
Fredonia is a city in Louisa County, Iowa, with 222 residents (2020 Census). It sits at 591 ft (180 m) above sea level. The nearest town is Columbus Junction, 1.3 miles W.
- 222residents (2020 Census)
- 591 ftelevation · 180 m
- 0.2 sq miland area · 0.4 km²
- 1,474 / sq mipopulation density
- 52738ZIP code
About Fredonia
Fredonia is a city in Louisa County, Iowa, United States. The population was 222 at the time of the 2020 census. It is part of the Muscatine Micropolitan Statistical Area.
Text: Wikipedia · CC BY-SA 4.0
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Living in Fredonia
- Median household income
- $85,625
- Median home value
- $71,700
- Median age
- 25.6
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Map of Fredonia
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Fredonia Street View
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Open in Google Maps ›Fredonia, IA population
Fredonia had 222 residents in the 2020 Census.
| 2020 Census | 222 |
|---|---|
| Density | 1,474 per sq mi (569 per km²) |
Source: U.S. Census Bureau, Decennial Census.
Fredonia at a glance
| State | Iowa (IA) |
|---|---|
| County | Louisa County |
| Type | City |
| Population | 222 (2020) |
| Land area | 0.15 sq mi (0.4 km²) |
| Elevation | 591 ft (180 m) |
| Coordinates | 41.2843° N, 91.3392° W |
| ZIP code | 52738 |
| Census code (GEOID) | 1929055 |
Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.
Towns near Fredonia
- Columbus Junction1.3 mi W
- Columbus City2.5 mi SW
- Letts6.2 mi NE
- Cotter6.4 mi W
- Conesville6.6 mi N
- Grandview7.9 mi E
- Wapello10.8 mi SE
- Ainsworth11.2 mi W
- Crawfordsville11.4 mi SW
- Fruitland11.8 mi E
- Winfield12.1 mi SW
- Nichols13.6 mi N
Straight-line distance between town centers.
Frequently asked questions about Fredonia
What county is Fredonia in?
Fredonia is in Louisa County, Iowa.
What is the population of Fredonia, IA?
222 people lived in Fredonia at the 2020 Census.
What is the ZIP code of Fredonia, IA?
The ZIP code of Fredonia is 52738.
What is the elevation of Fredonia?
591 feet (180 m) above sea level.
What towns are near Fredonia?
Columbus Junction (1.3 mi), Columbus City (2.5 mi), Letts (6.2 mi), Cotter (6.4 mi), Conesville (6.6 mi).
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