Farragut

City in Fremont County, Iowa

View of Farragut, Iowa
Photo: Jared Winkler · CC BY-SA 4.0

Farragut is a city in Fremont County, Iowa, with 490 residents (2020 Census). It sits at 958 ft (292 m) above sea level. The nearest town is Riverton, 5.1 miles SW.

About Farragut

Farragut is a city in Fremont County, Iowa, United States. The population was 490 at the time of the 2020 census.

Text: Wikipedia · CC BY-SA 4.0

Farragut weather: 7-day forecast

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Living in Farragut

Median household income
$54,688
Median home value
$112,100
Median rent
$670/mo
Median age
47.8
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Map of Farragut

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Farragut, IA population

Farragut had 490 residents in the 2020 Census.

2020 Census490
Density1,221 per sq mi (472 per km²)

Source: U.S. Census Bureau, Decennial Census.

Farragut at a glance

StateIowa (IA)
CountyFremont County
TypeCity
Population490 (2020)
Land area0.40 sq mi (1.0 km²)
Elevation958 ft (292 m)
Coordinates40.7201° N, 95.4808° W
ZIP code51639
Census code (GEOID)1926985

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Farragut

Straight-line distance between town centers.

Frequently asked questions about Farragut

What county is Farragut in?

Farragut is in Fremont County, Iowa.

What is the population of Farragut, IA?

490 people lived in Farragut at the 2020 Census.

What is the ZIP code of Farragut, IA?

The ZIP code of Farragut is 51639.

What is the elevation of Farragut?

958 feet (292 m) above sea level.

What towns are near Farragut?

Riverton (5.1 mi), Shenandoah (6.3 mi), Anderson (8.6 mi), Sidney (8.8 mi), Imogene (11.2 mi).

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