Arlington

City in Fayette County, Iowa

Aerial view of Arlington, Iowa
Aerial view: USDA NAIP · USGS The National Map (public domain)

Arlington is a city in Fayette County, Iowa, with 419 residents (2020 Census). It sits at 1,129 ft (344 m) above sea level. The nearest town is Wadena, 6.3 miles N.

About Arlington

Arlington is a city in Fayette County, Iowa, United States. The population was 419 in the 2020 census, a decline from the 490 population in the 2000 census.

Text: Wikipedia · CC BY-SA 4.0

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Source: National Weather Service (NOAA).

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Living in Arlington

Median household income
$38,958
Median home value
$112,000
Median rent
$560/mo
Median age
54
Cost of living and demographics of Arlington ›

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Map of Arlington

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Arlington, IA population

Arlington had 419 residents in the 2020 Census.

2020 Census419
Density418 per sq mi (161 per km²)

Source: U.S. Census Bureau, Decennial Census.

Arlington at a glance

StateIowa (IA)
CountyFayette County
TypeCity
Population419 (2020)
Land area1.00 sq mi (2.6 km²)
Elevation1,129 ft (344 m)
Coordinates42.7488° N, 91.6710° W
ZIP code50606
Census code (GEOID)1902845

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Arlington

Straight-line distance between town centers.

Frequently asked questions about Arlington

What county is Arlington in?

Arlington is in Fayette County, Iowa.

What is the population of Arlington, IA?

419 people lived in Arlington at the 2020 Census.

What is the ZIP code of Arlington, IA?

The ZIP code of Arlington is 50606.

What is the elevation of Arlington?

1,129 feet (344 m) above sea level.

What towns are near Arlington?

Wadena (6.3 mi), Volga (7.5 mi), Strawberry Point (8.4 mi), Fayette (9.3 mi), Aurora (9.4 mi).

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