Staunton
Town in Clay County, Indiana

Staunton is a town in Clay County, Indiana, with 472 residents (2020 Census). It sits at 646 ft (197 m) above sea level. The nearest town is Billtown, 1.6 miles N.
- 472residents (2020 Census)
- 646 ftelevation · 197 m
- 0.3 sq miland area · 0.8 km²
- 1,445 / sq mipopulation density
- 47881ZIP code
About Staunton
Staunton is a town in Posey Township, Clay County, Indiana, United States. As of the 2020 census, Staunton had a population of 472. It is part of the Terre Haute Metropolitan Statistical Area.
Text: Wikipedia · CC BY-SA 4.0
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Living in Staunton
- Median household income
- $57,500
- Median home value
- $92,900
- Median rent
- $894/mo
- Median age
- 45.4
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Map of Staunton
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Open in Google Maps ›Staunton, IN population
Staunton had 472 residents in the 2020 Census.
| 2020 Census | 472 |
|---|---|
| Density | 1,445 per sq mi (558 per km²) |
Source: U.S. Census Bureau, Decennial Census.
Staunton at a glance
| State | Indiana (IN) |
|---|---|
| County | Clay County |
| Type | Town |
| Population | 472 (2020) |
| Land area | 0.33 sq mi (0.8 km²) |
| Elevation | 646 ft (197 m) |
| Coordinates | 39.4865° N, 87.1889° W |
| ZIP code | 47881 |
| Census code (GEOID) | 1872782 |
Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.
Towns near Staunton
- Billtown1.6 mi N
- Cloverland2.3 mi NW
- Seelyville4.2 mi W
- Brazil4.2 mi NE
- Knightsville6.0 mi NE
- Fontanet6.6 mi NW
- Harmony7.0 mi NE
- Burnett7.1 mi NW
- Cory7.3 mi S
- Center Point7.8 mi SE
- Lakewood8.6 mi SW
- Saline City8.8 mi S
Straight-line distance between town centers.
Frequently asked questions about Staunton
What county is Staunton in?
Staunton is in Clay County, Indiana.
What is the population of Staunton, IN?
472 people lived in Staunton at the 2020 Census.
What is the ZIP code of Staunton, IN?
The ZIP code of Staunton is 47881.
What is the elevation of Staunton?
646 feet (197 m) above sea level.
What towns are near Staunton?
Billtown (1.6 mi), Cloverland (2.3 mi), Seelyville (4.2 mi), Brazil (4.2 mi), Knightsville (6.0 mi).
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