Simonton Lake

Census-designated place in Elkhart County, Indiana

Aerial view of Simonton Lake, Indiana
Aerial view: USDA NAIP · USGS The National Map (public domain)

Simonton Lake is an unincorporated community (census-designated place) in Elkhart County, Indiana, with 4,710 residents (2020 Census). It sits at 787 ft (240 m) above sea level. The nearest town is Elkhart, 4.2 miles S.

About Simonton Lake

Simonton Lake is a census-designated place (CDP) in Elkhart County, Indiana, United States. As of the 2020 census, Simonton Lake had a population of 4,710.

Text: Wikipedia · CC BY-SA 4.0

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Living in Simonton Lake

Median household income
$75,673
Median home value
$266,800
Median rent
$1,108/mo
Median age
47
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Map of Simonton Lake

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Simonton Lake, IN population

Simonton Lake had 4,710 residents in the 2020 Census.

2020 Census4,710
Density1,399 per sq mi (540 per km²)

Source: U.S. Census Bureau, Decennial Census.

Simonton Lake at a glance

StateIndiana (IN)
CountyElkhart County
TypeCensus-designated place
Population4,710 (2020)
Land area3.37 sq mi (8.7 km²)
Water area0.47 sq mi (1.22 km²)
Elevation787 ft (240 m)
Coordinates41.7542° N, 85.9705° W
ZIP code46514
Census code (GEOID)1869840

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Simonton Lake

Straight-line distance between town centers.

Frequently asked questions about Simonton Lake

What county is Simonton Lake in?

Simonton Lake is in Elkhart County, Indiana.

What is the population of Simonton Lake, IN?

4,710 people lived in Simonton Lake at the 2020 Census.

What is the ZIP code of Simonton Lake, IN?

The ZIP code of Simonton Lake is 46514.

What is the elevation of Simonton Lake?

787 feet (240 m) above sea level.

What towns are near Simonton Lake?

Elkhart (4.2 mi), Edwardsburg (6.5 mi), Bristol (7.8 mi), Osceola (8.3 mi), Granger (8.5 mi).

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