Oxford

Town in Benton County, Indiana

View of Oxford, Indiana
Photo: Huw Williams (Huwmanbeing) · Public domain

Oxford is a town in Benton County, Indiana, with 1,165 residents (2020 Census). It sits at 738 ft (225 m) above sea level. The nearest town is Templeton, 2.2 miles E.

About Oxford

Oxford is a town in Oak Grove Township, Benton County, Indiana. The population was 1,165 at the 2020 census. It is part of the Lafayette, Indiana, Metropolitan Statistical Area.

Text: Wikipedia · CC BY-SA 4.0

Oxford weather: 7-day forecast

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Source: National Weather Service (NOAA).

Live webcams in Oxford

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Living in Oxford

Median household income
$51,522
Median home value
$121,800
Median rent
$758/mo
Median age
38.4
Cost of living and demographics of Oxford ›

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Map of Oxford

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Oxford Street View

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Oxford, IN population

Oxford had 1,165 residents in the 2020 Census.

2020 Census1,165
Density2,128 per sq mi (822 per km²)

Source: U.S. Census Bureau, Decennial Census.

Oxford at a glance

StateIndiana (IN)
CountyBenton County
TypeTown
Population1,165 (2020)
Land area0.55 sq mi (1.4 km²)
Elevation738 ft (225 m)
Coordinates40.5215° N, 87.2482° W
ZIP code47971
Census code (GEOID)1857546

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Oxford

Straight-line distance between town centers.

Frequently asked questions about Oxford

What county is Oxford in?

Oxford is in Benton County, Indiana.

What is the population of Oxford, IN?

1,165 people lived in Oxford at the 2020 Census.

What is the ZIP code of Oxford, IN?

The ZIP code of Oxford is 47971.

What is the elevation of Oxford?

738 feet (225 m) above sea level.

What towns are near Oxford?

Templeton (2.2 mi), Pine Village (5.0 mi), Boswell (6.7 mi), Fowler (7.6 mi), Rainsville (8.2 mi).

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