Ferdinand

Town in Dubois County, Indiana

View of Ferdinand, Indiana
Photo: Chris Light at English Wikipedia · CC BY-SA 3.0

Ferdinand is a town in Dubois County, Indiana, with 2,157 residents (2020 Census). It sits at 538 ft (164 m) above sea level. The nearest town is St. Meinrad, 4.4 miles S.

About Ferdinand

Ferdinand is a town in Ferdinand Township, Dubois County, in the U.S. state of Indiana. The population was 2,157 at the 2020 census.

Text: Wikipedia · CC BY-SA 4.0

Ferdinand weather: 7-day forecast

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Living in Ferdinand

Median household income
$70,000
Median home value
$187,900
Median rent
$807/mo
Median age
50.4
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Map of Ferdinand

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Ferdinand, IN population

Ferdinand had 2,157 residents in the 2020 Census.

2020 Census2,157
Density902 per sq mi (348 per km²)

Source: U.S. Census Bureau, Decennial Census.

Ferdinand at a glance

StateIndiana (IN)
CountyDubois County
TypeTown
Population2,157 (2020)
Land area2.39 sq mi (6.2 km²)
Water area0.04 sq mi (0.10 km²)
Elevation538 ft (164 m)
Coordinates38.2280° N, 86.8625° W
ZIP code47532
Official websiteferdinandindiana.org
Census code (GEOID)1822990

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Ferdinand

Straight-line distance between town centers.

Frequently asked questions about Ferdinand

What county is Ferdinand in?

Ferdinand is in Dubois County, Indiana.

What is the population of Ferdinand, IN?

2,157 people lived in Ferdinand at the 2020 Census.

What is the ZIP code of Ferdinand, IN?

The ZIP code of Ferdinand is 47532.

What is the elevation of Ferdinand?

538 feet (164 m) above sea level.

What towns are near Ferdinand?

St. Meinrad (4.4 mi), Bretzville (4.7 mi), Mariah Hill (5.6 mi), St. Anthony (6.6 mi), Dale (7.0 mi).

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