Seville

Census-designated place in Volusia County, Florida

Aerial view of Seville, Florida
Aerial view: USDA NAIP · USGS The National Map (public domain)

Seville is an unincorporated community (census-designated place) in Volusia County, Florida, with 580 residents (2020 Census). It sits at 52 ft (16 m) above sea level. The nearest town is Crescent City, 6.3 miles N.

About Seville

Seville is an unincorporated community and census-designated place in Volusia County, Florida, United States, founded in 1882. As of the 2020 census, Seville had a population of 580.

Text: Wikipedia · CC BY-SA 4.0

Seville weather: 7-day forecast

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Living in Seville

Median household income
$143,368
Median home value
$418,300
Median age
34.5
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Map of Seville

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Seville, FL population

Seville had 580 residents in the 2020 Census.

2020 Census580
Density82 per sq mi (32 per km²)

Source: U.S. Census Bureau, Decennial Census.

Seville at a glance

StateFlorida (FL)
CountyVolusia County
TypeCensus-designated place
Population580 (2020)
Land area7.10 sq mi (18.4 km²)
Water area1.03 sq mi (2.67 km²)
Elevation52 ft (16 m)
Coordinates29.3369° N, 81.5092° W
ZIP code32190
Census code (GEOID)1265200

Sources: U.S. Census Bureau (Gazetteer, ZCTA), USGS GNIS, Wikidata.

Towns near Seville

Straight-line distance between town centers.

Frequently asked questions about Seville

What county is Seville in?

Seville is in Volusia County, Florida.

What is the population of Seville, FL?

580 people lived in Seville at the 2020 Census.

What is the ZIP code of Seville, FL?

The ZIP code of Seville is 32190.

What is the elevation of Seville?

52 feet (16 m) above sea level.

What towns are near Seville?

Crescent City (6.3 mi), Pierson (7.3 mi), Astor (11.9 mi), Pomona Park (12.6 mi), Bunnell (12.7 mi).

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